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If H2(g)+Cl2(g)→ 2HCl, ^@=-44 kcal ...

`If `H_2(g)+Cl_2(g)→ 2HCl`,
`^@=-44 kcal`
`2Na(s)+2HCl(g→ )2NaCl(s)+H_2(g),`
`△ H =-152 kcal` then,
`Na(s)+0.5Cl_2(g)→ NaCl(s),△ H `=?`

A

108 kcal

B

196 kcal

C

`-98 kcal`

D

54 kcal

Text Solution

Verified by Experts

The correct Answer is:
B
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