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If heat of neutralisation is -13.7 k cal...

If heat of neutralisation is -13.7 k cal and `H_f^(@)H_2O`=-68 k cal`, then enthalpy of `OH^- `would be:

A

54.3 k cal

B

`-54.3 k cal`

C

71.3 k cal

D

None

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The correct Answer is:
B
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