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H2(g)+Cl2(g)→2HCl(g), triangleH298K=-22....

`H_2(g)+Cl_2(g)→2HCl(g)`, `triangleH`298K=-22.06 kcals, For this reaction, `△U is equal to:

A

`-22.06 + 2 xx 10^-3 xx298 xx 2 kcal`

B

`-22.06 -2xx 298 kcal`

C

`-22.06 -2xx 298xx 4 kcal`

D

`-22.06 kcl`

Text Solution

Verified by Experts

The correct Answer is:
D
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