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H2+1/2O2rarrH2O, triangle H=-68.39 kcal ...

`H_2+1/2O_2rarrH2O`, `triangle H`=-68.39 kcal (i)
`K+aqrarrKOH(aq)+1/2H_2`, `triangleH=-48 kcal`
(ii) KOH+aqrarrKOH(aq):` `triangleH=-14 kcal `(iii)T he heat of formation(in kcal) of KOH is:

A

`-68.39+48-14`

B

`-68.39-48-14`

C

`68.39-48+14`

D

68.39+48+14

Text Solution

Verified by Experts

The correct Answer is:
B
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