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The enthalpy of formation of ammonia is ...

The enthalpy of formation of ammonia is -46.0kJ `mol^-1.` The enthalpy change for the reaction, `2NH_3(g)rarrN_2(g)+3H_2(g) is:`

A

`46.0 kJ mol^-1`

B

`92.0 kJ mol^-1`

C

`-23.0 kJ mol^-1`

D

`-92.0 kJ mol^-1`

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The correct Answer is:
B
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