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If CH3COOH+OH^-=CH3COO^-+H2O+q1 and H^+ ...

If `CH_3COOH+OH^-=CH_3COO^-+H_2O+q_1 and H^+ OH^-=H_2O+q_2` then the enthalpy change for the reaction, `CH_3COOH=CH_3COO^(-)+H^+,` is equal to:

A

`q_1+q_2`

B

`q_1-q_2`

C

`q_2-q_1`

D

`-q_1-q_2`

Text Solution

Verified by Experts

The correct Answer is:
B
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