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H2(g)+I2(g)rarr2HI(g), triangleH=-12.40 ...

`H_2(g)+I_2(g)rarr2HI(g), triangleH=-12.40 kcals`, Heat of formation of HI will be

A

12.4 kcal

B

`-12.4 kcal`

C

`-6.20 kcal`

D

6.20 kcal

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The correct Answer is:
D
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