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H2(g)+1/2O2(g)=H2O(l), triangleH298k=-...

`H_2(g)+1/2O_2(g)=H_2O(l)`,
`triangleH_298k`=-68.32 kcal. Heat of vaporisation of water at 1 atm and `25^@C `is 10.52 kcal. The standard heat of formation(in kcal) of 1 mole of water vapour at `25^@C` is:

A

`-78.84`

B

78.84

C

`+57.80`

D

`-57.80`

Text Solution

Verified by Experts

The correct Answer is:
D
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