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40% of a mixture of 0.2 mole of N2 and ...

`40%` of a mixture of 0.2 mole of `N_2` and o.6 mole of `H_2` react to give `NH_3` according to the equation: `N_ 2 ( g ) + 3 H_ 2 ( g ) ⇔ 2 N H_ 3` (g) at constant temperature and pressure. Then what is the ratio of the final volume to the initial volume of gases ?

A

4:5

B

5:4

C

7:10

D

8:5

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The correct Answer is:
A
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