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The decomposition of N2O4 to NO2 is carr...

The decomposition of `N_2O_4 to NO_2` is carried out at 280 K in chloroform.When equiliberium has been established,0.2 mole of `N_2O_4` and `2 xx 10^(-3)` mole of `NO_2` are present in a 2 litre solution. THE equiliberium constant for the reaction, `N_2O_4 ⇌ 2NO_2` is :

A

`1 xx 10^(-2)`

B

`1 xx 10^(-3)`

C

`1 xx 10^(-5)`

D

`2 xx 10^(-5)`

Text Solution

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The correct Answer is:
C
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