Name and give the formula of the compound formed when `SO_3` IS treated with heavy water.

When SO_2 reacts with water, the compound formed is

A compound 'A' having molecular formula C_(2)H_(5)O_(2)N , on reaction with Sn and conc. HCl gives a compound B which when treated with NaNO_(2) and dil. HCl gave compound C having molecular formula C_(2)H_(6)O . The compound C when treated with Na metal give effervescenes and when reacts with CrO_(3) give a saturated aldehyde having 2 carbon atoms. Determine the structures and names of A, B and C along with the sequence of reactions.

The formula of heavy water is :

Write the name of the following compounds : Fe(SO_4)_3

Primary alkyl halide C_(4)H_(9)Br (A) reacted with alcoholic KOH to give compound B. Compound B is reacted with HBr to give C which is an isomer of A. When A is reacted with sodium metal, it gives compound D, C_(8)H_(18) which is different from the compound formed when n-butyl bromide is reacted with sodium. Give the structural formula of A and write the equations for all the reactions.

C_2H_5O_2N on reaction with Sn and conc. HCL gives a compound 'B' which when treated with NaNO_2 and HCL gave the compound 'C' having M.F C_2H_6O .Then compound 'C ' when treated with 'Na' metal gives effervescence and when react with CrO_3 gives a saturated aldehyde.Determine structures and name of A, B,C.