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Derive the expression for emf induced in...

Derive the expression for emf induced in a straight conductor moving perpendicular to a uniform magnetic field.

Text Solution

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Magnetic flux enclosed by the loop is given by
`h phi = Blx`
From Faraday.s law, `ul("magnitude")` of induced emf is given by,
`e = (d phi)/(dt)`
Arriving at e= Blv " " :. (dx)/(dt)=v`
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