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Current in a coil falls from 2.5a to 0.0...

Current in a coil falls from 2.5a to 0.0a in 0.1 second inducing an emf of 200v.calculate the value of self inductance .

Text Solution

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`E - L (dI)/(dt)`
`200 = L (2.5)/(0.1)=25L`
`L = 8H`
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