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Current in a coil falls from 5 A to 0 A ...

Current in a coil falls from 5 A to 0 A in 0.1 s, calculate the induced emf in a coil if its self inductance is 4H.

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When the current in the coil falls from 5A to 0A in 0.15. The induced emf in a coil is ,
`E = L (dI)/(dt)`
`E= 4xx (5)/(0.1) = 200V`
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