A force F is related to the position of a particle by the relation `F = (10x^2) N`. The work done by the force when the particle moves from x= 2 m to x = 4 m is 

Options

A. `56/3 J`
B. `560J`
C. `560/3 J`
D. `3/560 J`

Answer

C

Explanation

`W = int_2^4 F dx = int_2^4 10 x^2 dx = [(10 x^3)/(3)]_(2)^(4)`
`= 10/3 [4^3 - 2^3] = 10/3 xx 56 = 560/3 J`