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A man drags a block through 10 mon rough...

 A man drags a block through 10 mon rough surface `(mu=0.5)`. A force of `sqrt(3)` kN` acting at `30^@` to the horizontal. The work done by applied force is 

A

zero

B

15 kJ

C

5 kJ

D

10 kJ

Text Solution

Verified by Experts

The correct Answer is:
B

The component of applied force F in the direction of motion is `F cos 30^@.`
The work done by the applied force is
`W = (F cos 30^@)S = sqrt(3) xx 10^(3) xx (sqrt3)/(2) xx 10 J = 15 xx 10^3 J = 15 kJ`
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