If the linear momentum is increased by 50%, then kinetic energy will be increased by 

Options

A. 50%
B. 100%
C. 125%
D. 25%

Answer

C

Explanation

Kinetic energy of a body, `K = (p^2)/(2m)`
where p is the momentum of the body and m is the mass of the body.
`p. = p + (50)/(100) p = 3/2 p`
Assuming m remains constant
`:. (K^.)/(K) = ((P.)/(P))^(2) = 9/4`
% increase in kinetic energy = `(K. - K)/(K) xx 100%`
`= ((K.)/(K) - 1) xx 100% = (9/4 - 1) xx 100% = 125%`.