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In the non-relativistic regime, if the m...

In the non-relativistic regime, if the momentum, is increased by 100%, the percentage increase in kinetic energy is 

A

100%

B

200%

C

3

D

400%

Text Solution

Verified by Experts

The correct Answer is:
C

Kinetic energy , `K = (p^2)/(2m)`
Since m remains costant , so `K prop p^2`
`:. (K_1)/(K_2) = ((p_1)/(p_2))^(2) = 1/4 " or " K_2 = 4K_1`
Percentage increase in kinetic energy = `(K_2 - K_1)/(K_1) xx 100%`
`= (4K_1 - K_1)/(K_1) xx 100% = 300%`.
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