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The displacement x and time for a partic...

The displacement x and time for a particle are related to each other as `t = sqrt(x) + 3`. What is work done in first six seconds of its motion? 

A

6J

B

zero

C

4J

D

2J

Text Solution

Verified by Experts

The correct Answer is:
B

From `sqrt(x) + 3 = t, x = (t - 3)^2`
Now, `v = (dx)/(dt) = 2(t -3)`
At `t = 0, v_1 = 2(-3) = -6`
At `t = 6 , v_2 = 2(6 - 3) = 6`
Work done = Change in KE = `1/2 m (v_2^2 - v_1^2)` = zero.
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