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A block of mass 10 kg is moving in x-dir...

A block of mass 10 kg is moving in x-direction with a constant speed of `10 ms^(-1)`. It is subjected to a retarding force `F = - 0.1x J m^(-1)` during its travel from x = 20 m to x = 30 m. Its final kinetic energy will be 

A

475 J

B

450 J

C

275 J

D

250 J

Text Solution

Verified by Experts

The correct Answer is:
A
According to work energy theorem , `K_f - K_i = W `
`:. K_f - 1/2 xx 10 xx 10^(2) = int F dx or K_f - 500 = int_(20)^(30) - 0.1 x dx`
or `K_f - 500 = -0.1 [(x^2)/(2)]_(20)^(30) = - 0.1 [(900 - 400)/(2)] = -25`
or `K_f = 500 - 25 = 475 J`.
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