Power supplied to a particle of mass 2 kg varies with time as `P= (3t^2)/(2)`, where t is in seconds. If velocity 2 of particle at t = 0 is v = 0, the velocity of particle at t = 2 s will be 

Options

A. `1 m//s`
B. ` 4 m//s`
C. `2 m//s`
D. `272 m//s`

Answer

C

Explanation

From work - energy theorem , `Delta KE = W_("net")`
`:. K_f - K_i = int Pdt " or " 1/2 mv^2 - 0 = int_0^2 (3/2 t^2) dt`
or `1/2 (2) v^2 = 3/2 [(t^3)/(3)]_(0)^(2) = 4 " or " v = 2 m//s` .