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A particle of mass m moving towards the east with speed v collides with another particle of the same mass and same speed v moving towards the north. If the two particles stick to each other, the new particle of mass 2m will have a speed of 

A

`v`

B

`v/2`

C

`v/(sqrt2)`

D

`vsqrt(2)`

Text Solution

Verified by Experts

The correct Answer is:
C
It is a case of perfectly inelastic collision.
According to law of conservation of linear momentum, we get
`m^2 v^2 + m^2v^2 = (2 mV)^(2)`
where V is the common velocity after the collision.
Solving , we get , `V = v/(sqrt2)`.
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