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A mass m moves with a velocity v and col...

A mass m moves with a velocity v and collides inelastically with another identical mass at rest. After collision, the first mass moves with velocity `v/(sqrt3)` in a direction perpendicular to Before collision the initial direction of motion. The speed of the `2^(nd)` mass after collision 

A

`(2v)/(sqrt3)`

B

`v/(sqrt3)`

C

`v`

D

`sqrt(3)v`

Text Solution

Verified by Experts

The correct Answer is:
A

In x-direction `mv + 0 = 0 + mv_1 cos theta " " ….(i)`
where `v_1` is the velocity of `2^(nd)` mass.
In y-direction
`0 = (mv)/(sqrt3) - mv_1 sin theta`
or `mv_1 sin theta = (mv)/(sqrt3) " " …….(ii)`
Squaring and adding equs. (i) and (ii), we get
`v_1^2 = v^2 + (v^2)/(3) = (4v^2)/(3) :. v_1 = (2v)/(sqrt3)` .
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Knowledge Check

  • A mass ‘m’ moves with a velocity ‘v’ and collides inelastically with another identical mass at rest. After collision the 1st mass moves with velocity (v)/(sqrt(3)) in a direction perpendicular to the initial direction of motion. Find the speed of the 2^(nd) mass after collision :

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