A spherical ball A of mass 4 kg, moving along a straight line strikes another spherical ball B of mass 1 kg at rest. After the collision, A and B move with velocities `v_1 ms^(-1) and v_2 m s^(-1)` respectively making angles of `30^@`   and `60^(@)` with respect to the original direction of motion of A. The ratio `(v_1)/(v_2)` will be

Options

A. `(sqrt3)/(4)`
B. `4/(sqrt3)`
C. `1/(sqrt3)`
D. `sqrt(3)`

Answer

A

Explanation

Applying the law of conservation of linear momentum along a direction perpendicular to the direction of motion (i.e., along y -axis) , we get `0 + 0 = 4v_1 sin 30^@ - v_2 sin 60^@`
`(v_1)/(v_2) = (sin 60^@)/(4 sin 30^@) = (sqrt3)/(4)`.