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If A={-1,1}, find A xx A xx A...

If A={-1,1}, find `A xx A xx A`

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The correct Answer is:
`A xx A xx A = {(1, 1, 1) (1,2,1)(1, 2,2)(1,1,2) (2,1,2) (2,2,1) (2,1,1) (2,2,2)}`
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