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Show that the middle term in the expansi...

Show that the middle term in the expansion of `(x-1/x)^(2n)` is `(1xx3xx5xx....xx(2n-1))/(n!) xx(-2)^(n)`

Text Solution

Verified by Experts

The correct Answer is:
Middle term = `(-2)^(n){(1xx3xx5xx7...(2n-1))/(n!)}`
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