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Divide 32 into four parts which are in A...

Divide 32 into four parts which are in A.P. Such that the product of extremes is to the product of means is `7: 15`

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The correct Answer is:
`2,6,10,14`
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KUMAR PRAKASHAN-SEQUENCE AND SERIES-Solutions of NCERT Exemplar Problems -Question of Module
  1. Divide 32 into four parts which are in A.P. Such that the product of e...

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  2. The terms 1,1,2,3,5,8,13,……respresents which sequence?

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  3. Which is the sequence whose terms are not finite?

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  4. What does a(1) + a(2) + a(3) + …..+ a(n) represent

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  5. Give new series by adding 2 in each term of arithmetic sequence 2,4,6,...

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  6. Find twelveth term of A.P. 4, 8, 12…….

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  7. 3 + 6+ 9 +…….Find sum of n terms.

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  8. 4 + 8 + 12+…….Find sum of first 15 terms.

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  9. Obtain arithmetic mean of 2 and 128

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  10. Insert 5 arithmetic mean between 3 and 4.

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  11. Find 8^(th) term of geometric sequence 3, 6,12,….

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  12. Find n^(th) term of Geometric sequence 1,3,9,27,……

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  13. Find S(n) for geometric sequence 4, 8, 15, 32,……

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  14. Find sum of first 10 terms of geometric series 3,9, 27,……

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  15. Find geometric mean of numbers 5 and 125.

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  16. Insert 3 geometric mean between 4 and 64.

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  17. The arithmetic and geometric mean of two positive numbers are 8 and 4 ...

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  18. If A and G be A.M. and G.M., respectively between two positive numbers...

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  19. Find value : 5^(2) + 6^(2) + 7^(2)+ …….+ 25^(2)

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  20. Prove the following by using the principle of mathematical induction f...

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