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If theta(1), theta(2), theta(3), theta(4...

If `theta_(1), theta_(2), theta_(3), theta_(4),….., theta_(n)` are in AP whose common difference is d, show that `sec theta_(1) sec theta_(2) + sec theta_(2) sec theta_(3)+ ………+ sec theta_((n-1)) sec theta_(n)= (tan theta_(n)- tan theta_(1))/(sin d)`

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The correct Answer is:
`tan theta_(n)- tan theta_(1)`
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