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Let S(n) denote the sum of the cubes of ...

Let `S_(n)` denote the sum of the cubes of the first n natural numbers and `S'_(n)` denote the sum of the first n natural numbers, then `underset(r=1)overset(n)Sigma ((S_(r))/(S'_(r)))` equals to

A

`(n(n+1) (n+2))/(6)`

B

`(n(n+1))/(2)`

C

`(n^(2) + 3n+ 2)/(2)`

D

None of these

Text Solution

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The correct Answer is:
A
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