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Find equation of circle whose end points...

Find equation of circle whose end points of diameter are centres of the circle `x^(2) + y^(2) + 6x - 14y - 1 =0 and x^(2) + y^(2) - 4x + 10y - 2 = 0`.

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The correct Answer is:
`x^(2) + y^(2) + x - 2y + 41 = 0`
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