Home
Class 11
MATHS
The equation of the circle having centre...

The equation of the circle having centre at (3, -4) and touching te line 5x + 12y - 12 = 0 is ……

Text Solution

Verified by Experts

The correct Answer is:
`(45)^(2)`
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • CONIC SECTIONS

    KUMAR PRAKASHAN|Exercise SOLUTIONS OF NCERT EXEMPLAR PROBLEMS (OBJECTIVE TYPE QUESTIONS)|13 Videos

  • CONIC SECTIONS

    KUMAR PRAKASHAN|Exercise QUESTION OF MODULE|9 Videos

  • CONIC SECTIONS

    KUMAR PRAKASHAN|Exercise SOLUTIONS OF NCERT EXEMPLAR PROBLEMS (TRUE/FALSE)|8 Videos

  • COMPLEX NUMBERS AND QUADRATIC EQUATIONS

    KUMAR PRAKASHAN|Exercise (Questions of Module) (Knowledge Test :)|15 Videos

  • INTRODUCTION TO THREE DIMENSIONAL GEOMETRY

    KUMAR PRAKASHAN|Exercise QUESTION OF MODULE (KNOWLEDGE TEST :)|12 Videos

Similar Questions

Explore conceptually related problems

Obtain equation of circle in Centre (3,4) Touches X - axis.

Obtain equation of circle in Centre (-3,4) Touches X - axis.

Find the equation of the circle having (1, -2) as its centre and passing through 3x + y = 14, 2x + 5y = 18.

Find the equation of a circle which touches both the axes and the line 3x - 4y + 8 = 0 and lies in the third quadrant.

x intercept of line 4x + 3y - 12 is 3.

x intercept of line 4x + 3y - 12 is 3.

Find the equation of the circle which touches X - axis and whose centre is (1,2).

Find the equation of a circle whose centre is (3, -1) and which cuts off a chord of length 6 units on the line 2x - 5y + 18 = 0.

Let P be the point on the parabola, y^2=8x which is at a minimum distance from the centre C of the circle, x^2+(y+6)^2=1. Then the equation of the circle, passing through C and having its centre at P is : (1) x^2+y^2-4x+8y+12=0 (2) x^2+y^2-x+4y-12=0 (3) x^2+y^2-x/4+2y-24=0 (4) x^2+y^2-4x+9y+18=0

Find the equation of a circle of radius 5 which is touching another circle x^(2) + y^(2) - 2x - 4y - 20 = 0 at (5,5).

Home
Profile