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MBD-INTRODUCTION TO TRIGONOMETRY-EXERCISE
- Prove the following : (sintheta-costheta+1)/(sintheta+costheta-1)=(1)/...
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- Prove the following : tan^2A-tan^2B=(sin^2A-sin^2B)/(cos^2Acos^2B) .
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- (sec A - cos A) (cot A + tan A) = tan A sec A.
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- sin A (1 + tan A) + cos A (1 + cot A) = sec A + cosec A .
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- (cosec theta -sin theta) (sec theta - cos theta) (tan theta + cot thet...
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- (1 + cot A — cosec A) (1 + tan A + sec A) = 2 .
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- (sintheta+cosectheta)^2+(costheta+sectheta)^2=tan^2theta+cot^2+7 .
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- tan^2theta+cot^2theta+2=sec^2thetacoses^2theta .
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- Prove that cosA/(1-tanA)-(sin^2A)/(cosA-sinA)== sin A + cos A. .
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- (1+sintheta)/(1-sintheta)=1+(2tantheta)/costheta+2tan^2theta .
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- Prove tantheta/(sectheta-1)+(tantheta)/(sectheta+1)=2cosectheta .
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- (1+costheta+sintheta)/(1+costheta-sintheta)=(1+sintheta)/costheta .
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- Prove the following identities, where the angles involved are acute an...
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- tantheta/(1-cottheta)+cottheta/(1-tantheta)=1+tantheta+cottheta .
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- (sinA+cosA)/(sinA-cosA)+(sinA-cosA)/(sinA+cosA)=2/(sin^2A-cos^2A)=2/(1...
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- (tan^3theta)/(1+tan^2theta)+(cot^3theta)/(1+cot^2theta)=secthetacosect...
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- 2sec^2theta-sec^4theta-2cosec^2theta+cosec^4theta=cot^4theta-tan^4thet...
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- Prove that (sintheta)/(1+costheta)+(1+costheta)/sintheta=2cosectheta .
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- (tanA+secA-1)/(tanA-secA+1)=(1+sinA)/cosA .
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- 1/(cosectheta+cottheta)-1/sintheta=1/sintheta-1/(cosectheta-cottheta) ...
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