If P(E) = 0.05, which is the probability of not E.

E_1 and E_2 are equally likely events associated with an experiment. If P(E_1)=p what is the probability of E_2 ?

If P (E) = 0.05 than find the value of P (Not E) ?

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that neither E_1 nor E_2 occurs.

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that both E_1 and E_2 occur.

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that one and only one event happens.

There are two independent events E_1 and E_2 and P(E_1)=0.30 , P(E_2)=0.60 find the probability that at least one of E_1 and E_2 happens.

If P (E) denotes probability of occurrence of event E, then :

True|false: use the theoretical probability of an event 'E' is 0.47, use the theoretical probability of event 'not E' is 0.53?

What will be the probability of event E + event not E ?

Let {E_(1), E_(2), ..., E_(n),} be a partition of the sample space S, and suppose that each of the events E_(1), E_(2)...., E_(n) , has non-zero probability of occurrence. Let A be any event associated with S, then P(A) = P(E_(1)) P(A|E_(1))+ P(E_(2)) P(A|E_(2)) +...+P(E_(n)) P(A|E_(n))