Figure shows a box of mass m is placed on a wedge of mass .M. on a smooth surface. How much force .F. is required to be applied on .M. so that during motion .m. remains at rest on its surface .

Explanation

The force action on the bodies m and M are shown in the figure along with free body diagrams of mass m and M. As the two bodies move together, we can find the acceleration of system towards right directly as
`a=F/(m+M)`

Here the condition is , the small block of mass .m. should remain at rest on the incline surface of the wedge block. Look at the FBD of m, the force acting on it towards left is .ma. . It is teh pseudo force on it as its reference frame is the wedge . As wedge . As wedge is moving with an acceleration , we consider m relative to it . Now with respect to wedge block m is at rest or in equilibrium , we can balance all the forces along the tendency of motion of body (i.e., inclined plane) and perpendicular to it shown in FBD of it.
For m to be at rest , from FBD of m , along the plane
mg `sin theta = ma cos theta "or" a =g tan theta "or" F/(m+M)=g tan theta , F=(m+M) g tan theta`