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Why AI(HO)(3) is insoluble in excess of ...

Why `AI(HO)_(3)` is insoluble in excess of `NH_(4)OH` but soluble in `NaOH`?

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NaOH is strong alkali than `NH_(4)OH and AI(OH)_(3)` being amphoteric dissolves in NaOH due to the formation os soluble `NaAIO_(2)`.
`I(OH)_(3)+NaOHrarrNaAIO_(2) + 2H_(2)O`
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