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A square of side "a" lies above the x-ax...

A square of side "a" lies above the x-axis and has one vertex at the origin. The side passing through the origin makes an angle `alpha " where " oltalphaltpi/4` with the positive direction of x-axis, the equation of its diagonal not passing through the origin is

A

`(cosalpha+sinalpha)+x(cosalpha-sinalpha)=a`

B

`(cosalpha-sinalpha)-x(cosalpha-sinalpha)=a`

C

`(cosalpha+sinalpha)+x(cosalpha-sinalpha)=a`

D

`(cosalpha+sinalpha)+x(cosalpha+sinalpha)=a`

Text Solution

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The correct Answer is:
A
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Knowledge Check

  • A square of side a lies above the x-axis and has one vertex at the origin. The side passing through the origin makes an angle alpha(0 lt alpha lt (pi)/(4)) with the positive direction of x-axis. The equationof its diagonal not passing through the origin is

    A
    `y(cos alpha - sin alpha) - x (sin alpha-cos alpha)=a`
    B
    `y(cos alpha+sin alpha)+x (sin alpha-cos alpha)=a`
    C
    `y(cos alpha+sin alpha)+x(sinalpha+sinalpha)=a`
    D
    `y(cos alpha+sin alpha)+x (cos alpha-sin alpha)=a`

  • The number of lies perpendicular to Y -axis lying in XZ plane and passing through the origin is

    A
    1
    B
    2
    C
    3
    D
    Infinite

  • The equation of the line perpendicular to the line 2x+3y-4=0 and passing through the origin is

    A
    `y=0`
    B
    `4x+5y-38=0`
    C
    `3x-2y=0`
    D
    `3x-2y-1=0`

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