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A square of side "a" lies above the x-ax...

A square of side "a" lies above the x-axis and has one vertex at the origin. The side passing through the origin makes an angle `alpha " where " oltalphaltpi/4` with the positive direction of x-axis, the equation of its diagonal not passing through the origin is

A

`(cosalpha+sinalpha)+x(cosalpha-sinalpha)=a`

B

`(cosalpha-sinalpha)-x(cosalpha-sinalpha)=a`

C

`(cosalpha+sinalpha)+x(cosalpha-sinalpha)=a`

D

`(cosalpha+sinalpha)+x(cosalpha+sinalpha)=a`

Text Solution

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The correct Answer is:
A
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AAKASH SERIES-STRAIGHT LINES-LECTURE SHEET(EXERCISE-II Problems on form, symmetric form, Perpendicular distance and Ratio)( Straight Objective Type Question)
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