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Reflection of the line x+y+1=0 in the li...

Reflection of the line x+y+1=0 in the line.

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The reflection of the point (4, -13) in the line 5x+y+6=0 is

Write the equation of the reflection of the line x=1 in the Y-axis.

Knowledge Check

  • The reflection of the point A (1,0,0) in the line (x-1)/(2) = (y+1)/(-3) = (z+10)/(8) is

    A
    `(3,-4,-2)`
    B
    `(5, -8, -4)`
    C
    `(1, -1, 10)`
    D
    `(2, -3, 8)`
  • The reflection of the point (6, 8) in the line x = y is

    A
    (4, 2)
    B
    (-6, -8)
    C
    (-8, -10)
    D
    (8, 6)
  • The equation of the line passing through the point of intersection of the lines 2x+y+1=0, x-y-7=0 and the point (3, -2) is

    A
    `3x+y=0`
    B
    `3x+y-5=0`
    C
    `5x+2y=0`
    D
    `3x-y-11=0`
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    Find the image (reflection) of the line (i) x=1 in the y-axis (ii) y+2=0 w.r.t y=0

    Find the image of the line x-y-1=0 in the line 2x-3y+1=0 .

    The slope of the line 4x-5y-1=0 is

    A : The reflection of (6, 8) in the line x=y is (8, 6) R : The reflection of (x_(1), y_(1)) in the line x=y is (y_(1), x_(1))

    The equation of the straight line perpendicular to the straight line 3x+2y=0 and passing through the point of intersection of the lines x+3y-1=0 and x-2y+4=0 is