Home
Class 11
MATHS
A (1,3) and C (-2/5,-2/5) are the vertic...

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angular bisector of `angleABC is x+y -2=0`
Coordinates of vertex B

A

`(3/10,17/10)`

B

`(17/10,3/10)`

C

`(-5/2,9/2)`

D

(1,1)

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINES

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-IV Problems on Angle between lines, Foot, Image, Orthocentre, Circumcentre, Incentre, Angle Bisector and Locus) (LEVEL-II Integer Type Qeustions)|4 Videos
  • STRAIGHT LINES

    AAKASH SERIES|Exercise ADDITIONAL PRACTICE EXERCISE (LEVEL-I (MAIN) Straight Objective Type Questions)|10 Videos
  • STRAIGHT LINES

    AAKASH SERIES|Exercise PRACTICE SHEET (EXERCISE-IV Problems on Angle between lines, Foot, Image, Orthocentre, Circumcentre, Incentre, Angle Bisector and Locus) (LEVEL-II More than One correct answer Type Questions)|3 Videos
  • REVISION EXERCISE

    AAKASH SERIES|Exercise PROPERTIES OF TRIANGLES|57 Videos
  • TANGENT AND NORMAL

    AAKASH SERIES|Exercise ADVANCED SUBJECTIVE TYPE QUESTIONS|48 Videos

Similar Questions

Explore conceptually related problems

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of angleABC is x+y =2 Equation of BC is

A (1,3) and C (-2/5,-2/5) are the vertices of a triangle ABC and the equation of the angle bisector of angleABC is x+y =2 Equation of side AB is

A(10,4),B(-4,9) and C(-2,-1) are the vertices of a triangle.Find the equations of The perpendicular bisector of the side AB

The vertices of a trianvle are A(-1,-7),B(5,1) and C(1,4). The equation of the bisector of /_ABC is

If A(1, -1, -3), B(2, 1, -2), C(-5, 2, -6) are the vertices of a DeltaABC , then the length of internal bisector of angle A is

Equation of the acute angular bisector of the planes 2x-y-2z-6=0,3x+2y-6z-12=0 is