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The straight line x+y=0, 3x+y-4=0 and x+...

The straight line x+y=0, 3x+y-4=0 and x+3y-4=0 from a triangle which is

A

isosceles

B

right-angled

C

obtuse-angled

D

equilateral.

Text Solution

Verified by Experts

The correct Answer is:
A, C
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Knowledge Check

  • The straight lines x+3y-4=0, x+y -4 = 0 and 3x+y-4=0

    A
    form an isosceles triangle
    B
    are concurrent
    C
    form an equilateral triangle
    D
    form a right angled isoceles triangle

  • The straight lines x+ 3y -4=0,x+y-4=0 and 3x+y - 4 = 0

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    from an isosceles triangle
    B
    are concurrent
    C
    from an equilateral triangle
    D
    from a right angled isosceles triangle

  • If the lines x+y=0, x-y=0 and 2x+3y-6=0 are the sides of a triangle and (-2, a) is an interior point of the triangle then a lies

    A
    `2 lt a lt 10//3`
    B
    `-2 lt a lt 10//3`
    C
    `-1 lt a lt 9//2`
    D
    `-3 gt a gt 9//2`

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