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Equation of a bisector of the angle betw...

Equation of a bisector of the angle between the line `y-b=(2m)/(1-m^2)(x-a) and y-b=(2m')/(1-m^2)(x-a)` is

A

(y-b)(m+m ')+(x-a)(1-mm ')=0

B

(y-b)(m-m ')+(x-a)(1-mm ')=0

C

(y-b)(m+m ')-(y-b)(1-mm ')=0

D

(y-b)(m+m ')+(y-b)(1-mm ')=0

Text Solution

Verified by Experts

The correct Answer is:
(y-b)(1-mm')-(x-a)(m+m')=0
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