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The pair of lines a^(2)x^(2)+2h(a+b)xy+b...

The pair of lines `a^(2)x^(2)+2h(a+b)xy+b^(2)y^(2)=0 and ax^(2)+2hxy+by^(2)=0` are

A

two pairs of perpendicular straight lines

B

two pair of parallel straight lines

C

two pairs of straight lins which are equally inclined to each other

D

none of these

Text Solution

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The correct Answer is:
C
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AAKASH SERIES-PAIR OF STRAIGHT LINES-PRACTICE SHEET (EXERCISE-1 Homogeneous pair of line) (LEVEL-I Straight Objective Type Questions)
  1. If one of the lines of my^(2)+(1-m^(2))xy-mx^(2)=0 is a bisector of a...

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  2. If the pairs of straight lines x^(2)-2pxy-y^(2)=0 and x^(2)-2qxy-y^(2)...

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  3. The pair of lines a^(2)x^(2)+2h(a+b)xy+b^(2)y^(2)=0 and ax^(2)+2hxy+by...

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  4. The locus of the points equidistant from the pair of line x^2cos^2thet...

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  5. The straight lines represented by the equation 135x^2+136xy+33y^2=0 ar...

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  6. The combined equation of the lines l(1), l(2) is 2x^(2)+6xy+y^(2)=0 a...

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  7. If the lines x^(2)+(2+h)xy-4y^(2)=0 are equally inclincd to the coordi...

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  8. The area of the triangle formed by two rays whose combined equation is...

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  9. If the area of the triangle formed by the pair of lines 8x^(2)-6xy+y^(...

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  10. The area of the triangle formed by pair of line (ax+by)^2-3(bx-ay)^2=0...

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  11. The lines represented by the equation x^(2)-y^(2)-x+3y-2=0 are

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  12. If the equation 2x^2+5xy+3y^2+6x+7y+=0 represents a pair of lines, the...

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  13. If the angle alpha is acut, then the acute angle between the pair of s...

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  14. The value of lambda " such that " lambdax^2-10xy+12y^2+5x-16y-3=0 repr...

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  15. If the pair of lines given by (x^(2)+y^(2))cos^(2) theta=(x cos theta+...

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  16. The distance from a point (alpha,beta) to a pair of lines passing thro...

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  17. If x^(2)+4xy+4y^(2)+4x+cy+3 can be written as the product of two linea...

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  18. The equation x^2-5xy+py^2+3x-8y+2=0 represents a pair of straight line...

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  19. The angle between the pair of lines whose equation is 4x^2+10xy+my2+5...

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  20. The condition that one of the pair of lines ax^2+2hxy+by^2=0 be conici...

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