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If S=[(0,1,1),(1,0,1),(1,1,0)], A=(1)/(2...

If `S=[(0,1,1),(1,0,1),(1,1,0)], A=(1)/(2)[(b+c,c-a,b-a),(c-b,c+a,a-b),(b-c,a-c,a+b)]`, then `SAS^(-1)=`

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