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If abs(bara)=1,abs(barb)=1,abs(barc)=2 a...

If `abs(bara)=1,abs(barb)=1,abs(barc)=2` and `baraxx(baraxxbarc)+barb=bar0` then find the angle between `bara` and `barc`

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The correct Answer is:
`30^(@)"(or)"150^(@)`
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