IF cos theta ne 0, and sec theta-1=(sqrt...

IF `cos theta ne 0, and sec theta-1=(sqrt2-1) tan theta` then `theta=`

A

`theta = {(2 n pi)/(3), n in Z}cup{2 n pi + (pi)/(2), n in Z}`

B

`theta = {2 n pi, n in Z}cup {2 n pi + (pi)/(4) , n inZ}`

C

`theta = {(2 n pi)/(5), n in Z}cup {2 n pi + (pi)/(6), n in Z}`

D

`theta = {(2 n pi)/( 7), n in Z} cup {2 n pi + (pi)/(3) , n in Z}`

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The correct Answer is:

B

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