The equation 2sin^(3) theta+(2lamda-3)si...

The equation `2sin^(3) theta+(2lamda-3)sin^(2)theta-(3lamda+2)sin theta-2 lamda=0` has exactly three roots in `(0, 2 lamda)`,then `lamda` can be equal to

A

0

B

2

C

1

D

`-1`

Verified by Experts

The correct Answer is:

A, C, D

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