If sin^(3) theta cos theta - cos ^(3) th...

If `sin^(3) theta cos theta - cos ^(3) theta sin theta = 1 //4 " then " theta` =

A

`theta = (n pi)/( 2) + (pi)/(8) n in Z`

B

`theta = ( n pi)/(2) - (pi)/(8) n in Z`

C

`theta = (n pi)/(2) + (pi)/(4) n in Z`

D

`theta = (n pi)/(2) - (pi)/(4) n in Z`

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The correct Answer is:

B

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