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If sin x - 3 sin 2x + sin 3x = cos x - 3...

If `sin x - 3 sin 2x + sin 3x = cos x - 3 cos 2x + cos 3x` then x =

A

`n pi + (pi)/(8)`

B

`(n pi)/(2) + (pi)/(8)`

C

`(-1)^(n) (n pi)/(2) + (pi)/(8)`

D

`2 n pi + cos^(-1)""(2)/(3)`

Text Solution

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The correct Answer is:
B
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