If (cos (alpha - 3 theta))/( cos^(3) the...

If `(cos (alpha - 3 theta))/( cos^(3) theta)=(sin (alpha - 3 theta))/(sin^(3) theta)` = m then

A

`cos 2 alpha = (2 m^(2) - 9 m^(2) + 8)/( m^(2))`

B

`cos alpha = ( 2 - m^(2))/( m)`

C

`cos 2 alpha = (2 m^(2) + 9 m ^(2) + 8)/( m^(2))`

D

`cos alpha = ( 2 + m^(2))/(m)`

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The correct Answer is:

A, B

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