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f(x)=sin{cot^(-1)(x+1)}-cos(tan^(-1)x), ...

`f(x)=sin{cot^(-1)(x+1)}-cos(tan^(-1)x), a=costan^(-1)sincot^(-1)x, b=cos(2cos^(-1)x+sin^(-1)x)`
If `f(x)=0` then `a^(2)=`

A

`1//2`

B

`2//3`

C

`5//9`

D

`9//5`

Text Solution

Verified by Experts

The correct Answer is:
C
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