If tan h^(2) x = cos theta then cos h 2x...

If `tan h^(2) x = cos theta` then cos h 2x =

A

`tan^(2)((theta)/(2))`

B

`cot^(2)((theta)/(2))`

C

`sec^(2)((theta)/(2))`

D

`sin^(2)((theta)/(2))`

Verified by Experts

The correct Answer is:

B

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